Section 2.17  Interactive checkpoint: subway train  
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A subway train accelerates along a straight track at a constant 1.90 m/s2.
How long does it take the train to increase its speed from 4.47 m/s to 13.4 m/s?
 
 

Answer:

Δt = s

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Diagram  [Hide]

Variables  [Hide]

Fill in the known values.

Variable

Value

acceleration

a = m/s2

initial velocity

vi = m/s

final velocity

vf = m/s

elapsed time

Δt

I think I'm done. I need help. Show the correct values.
 
Strategy  [Hide]
  1. Select an equation that contains variables for the values you are given, and the one you want to calculate.
  2. Remember that the delta symbol Δ stands for a change. It means the final value minus the initial value. To solve the problem, expand the term that contains the Δ.
Physics principles and equations  [Hide]

v = Δxt

a = Δvt

Step-by-step solution   [Hide]
2

Select the equation that contains variables for the values you are given, and the one you want to calculate.

Expand equation

The delta symbol Δ stands for a change. The change in velocity is equal to the final velocity minus the initial velocity.

a = (vfvi)/Δt

Solve for elapsed time

Δt = (vfvi)/a

Enter values

Δt = ( m/s – m/s) / ( m/s2)

Evaluate

Δt = s

 
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